b^2+3b+28=

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Solution for b^2+3b+28= equation:


Simplifying
b2 + 3b + 28 = 0

Reorder the terms:
28 + 3b + b2 = 0

Solving
28 + 3b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-28' to each side of the equation.
28 + 3b + -28 + b2 = 0 + -28

Reorder the terms:
28 + -28 + 3b + b2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 3b + b2 = 0 + -28
3b + b2 = 0 + -28

Combine like terms: 0 + -28 = -28
3b + b2 = -28

The b term is 3b.  Take half its coefficient (1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
3b + 2.25 + b2 = -28 + 2.25

Reorder the terms:
2.25 + 3b + b2 = -28 + 2.25

Combine like terms: -28 + 2.25 = -25.75
2.25 + 3b + b2 = -25.75

Factor a perfect square on the left side:
(b + 1.5)(b + 1.5) = -25.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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